(3x^0/5y^-2)^0

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Solution for (3x^0/5y^-2)^0 equation: 


D( x )

x = 0

((3*x^0)/5)*y^-2 = 0

x = 0

x = 0

((3*x^0)/5)*y^-2 = 0

((3*x^0)/5)*y^-2 = 0

(3/5)*y^-2 = 0

3/5*y^-2 = 0

x należy do R

x belongs to the empty set

(((3*x^0)/5)*y^-2)^0 = 0

x belongs to the empty set

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